In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.
I. x^{2} – x – 600 = 0
II. y^{2} – 3y – 270 = 0Calculations:
I. x^{2} – x – 600 = 0
⇒ x^{2} – 25x + 24x – 600 = 0
⇒ x(x – 25) + 24(x – 25) = 0
⇒ (x – 25) (x + 24) = 0
⇒ x = 25, -24
II. y^{2} – 3y – 270 = 0
⇒ y^{2} – 18y + 15y – 600 = 0
⇒ y(y – 18) + 15(y – 18) = 0
⇒ (y – 18) (y + 15) = 0
⇒ y = 18, -15
Value of x |
Value of y |
Relation |
25 |
18 |
x > y |
25 |
-15 |
x > y |
-24 |
18 |
x < y |
-24 |
-15 |
x < y |